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Fraction On A Rulers

Introduction of Fraction Rulers:

Ruleris said to be scale which is used as a measuring device. Fraction also takes place in rulers. But it seems, that the rulers have denoted as in whole number in the unit of cm. Here we see rulers have 15 cm unit, in between each cm unit fraction exist. Division takes place in between each cm unit as we see below.

 fractioninscale

In this article, we see about the fraction rulers.


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Fraction Rulers – 0 to 1 cm unit:


  fractionfrom0to1cmunit

 

Step 1: Let the measurement taken from 0 to 1 unit cm

Step 2: We get the half of the unit as the fraction in rulers ½ by dividing the unit 0 to 1 by 2,

Step 3: Let see the unit zero to half (0 to ½) in rulers

Step 4: Divide the unit 0 to ½ by 2, we get the half of the fraction ½ is ¼ in rulers.

Step 5: Again see the unit 0 to ¼ half - half of the fraction as.

Step 5: We get the half of the fraction ¼ is 1/8 by dividing the unit 0 to ¼ by 2.

Step 6: Now see right side of the unit ½ to 1 cm unit and divide it by 2, we get ¾.

Step 7: Again split the possible fraction in ½ to ¾ and divide it by 2, we get 5/8.

Step 8: Again split the possible fraction from ¾ to 1 cm unit and divide it by 2, we get 7/8.


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Example Problem – Fraction Rulers:


Example 1:

Add the fraction `(1)/(4)` and `(5)/(8)` by using fraction rulers.

Solution:

 addthefractioninruler1/4and5/8

Here see the fraction ¼ to be added with the fraction 5/8.

¼ + 5/8 = 7/8

Procedure – Adding fraction on a fraction rulers:

Step 1: Take the rulers 1 and 2; Keep the fraction rulers 1 as it is.

Step 2: Take the fraction rulers 2 and place zero of the rulers 2 coincides with ¼ of the fraction rulers 1.

Step 3: Now see where the second fraction ruler of the `(5)/(8)` coincides with the fraction rulers 1.

Step 4: That be `(7)/(8)`

Thus the addition of the two fractions ¼ and  `(5)/(8)` is `(7)/(8)`  which is less than 1.

Answer:  `(1)/(4)` + `(5)/(8)` `(7)/(8)` 

Example 2:

Subtract the fractions ¼ from  `(9)/(16)` by using the fraction rulers.

Solution:

 sub1/4from9/16infractionrulers

Procedure for subtract the fraction in fraction rulers:

`(9)/(16)` – ¼ = `(5)/(16)`

Step 1:  Take the rulers 1 and 2; Keep the fraction rulers 1 as it is.

Step 2: Take the fraction rulers 2 and coincides the fraction 9/16 to the fraction rulers 1 of the fraction ¼.  

Step 3: Now see where the zero place of fraction rulers 1 is coincides with fraction rulers 2.

Step 4: That is `(5)/(16)`

Thus the subtraction of the two fractions ¼ from `(9)/(16)` is `(5)/(16)`.

`(9)/(16)``(1)/(4)` = `(5)/(16)`